Steven D'Aprano added the comment: Your description is hard to understand, and doesn't give enough detail, but I *think* I can guess what you might be referring to.
If you start with a really big integer, and divide, you get a float. But really big floats cannot represent every number exactly (they only have a limited precision). For example: py> n = 12345678901234567 py> print(n, n/1) 12345678901234567 1.2345678901234568e+16 Converting n to an int (you don't need to use division, calling float() will do the same thing) rounds to the nearest possible 64-bit floating point value, which happens to be one larger. If this is the error you are talking about, there's nothing that can be done about it. It is fundamental to the way floating point numbers work. If you mean something different, please explain. ---------- nosy: +steven.daprano _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue27708> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
