Serhiy Storchaka added the comment:
The simple way is just write all possible variants
('ENABLE.*NOAUTH|NOAUTH.*ENABLE').
The general way is to use itertools.permutations():
pattern = '|'.join(map('.*'.join, permutations(map(re.escape, strings))))
See also similar problem in issue19681. The first my patch used permutations().
But there was committed the patch with manually written variants.
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<http://bugs.python.org/issue27132>
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