Antti Haapala added the comment: This behaviour exists exactly because the return value also contains the `.hostname`, which for the IPv6 addresses is *without* brackets:
>>> urlparse('http://[::1]:80/').hostname '::1' There is no way to get a proper parsing result from such a broken URI. ---------- nosy: +ztane _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue27089> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com