New submission from Raymond Hettinger:
The docs for locals() say that inside a function that local variables and free
variables are included: https://docs.python.org/3/library/functions.html#locals
Elsewhere we use the terms "cell variables" or "nonlocals". Mathematically,
the word "free" means unbound, so that isn't applicable here and isn't the
usual way of describing variables in the enclosing scope.
>>> def f(x):
def g(y):
z = x + y
print(locals())
return g
>>> f(10)(20)
{'x': 10, 'y': 20, 'z': 30}
Also, I'm not sure why "x" and "y" are included in the definition for locals().
That seems strange given that "x" and "y" are not local to "g" and that "x +=
1" would fail with an UnboundLocalError.
----------
assignee: docs@python
components: Documentation
messages: 262713
nosy: docs@python, rhettinger
priority: normal
severity: normal
status: open
title: Questionable terminology for describing what locals() does
versions: Python 2.7, Python 3.5, Python 3.6
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue26683>
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