Raymond Hettinger added the comment:
[Emanuel Barry]
> In which circumstances does comparing two code objects
> (at function creation time, what's more) make any sense?
It makes closures efficient:
>>> def f(x):
def g(y):
return x + y
return g
>>> h = f(1)
>>> i = f(2)
>>> h.__code__ is i.__code__
True
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue25843>
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