New submission from Daniel Plachotich:
Since Windows 7 (or even Vista), Windows gives permission error(5,
ERROR_ACCESS_DENIED
if you try to create a directory in a drive root with the same name as a drive
itself,
even if you have administrative permissions. This behavior is not mentioned in
Microsoft docs.
Here is an example session (Windows 7, admin):
d:\>IF EXIST . echo True
True
d:\>mkdir .
Access is denied.
d:\>mkdir dir
d:\>cd dir
d:\dir>mkdir .
A subdirectory or file . already exists.
d:\dir>cd ..
d:\>
d:\>py -3
Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:43:06) [MSC v.1600 32 bit (In
tel)] on win32
>>> import os
>>> os.path.isdir('.')
True
>>> os.makedirs('.', exist_ok=True)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python34\lib\os.py", line 237, in makedirs
mkdir(name, mode)
PermissionError: [WinError 5] ...
>>> try:
... os.mkdir('.')
... except OSError as e:
... print(e.errno)
...
13
This means that if you want to write portable code, you still need to write
like in Python 2:
if not os.path.isdir(path):
os.makedirs(path)
Which makes exist_ok useless.
The actual problem is in this line (Lib/os.py#l243):
if not exist_ok or e.errno != errno.EEXIST or not path.isdir(name):
Due the reasons described above, makedirs shouldn't rely on e.errno, so the
right code will be:
if not (exist_ok and path.isdir(name)):
I think the issue is pretty serious to be backported.
----------
components: Library (Lib)
messages: 254339
nosy: Daniel Plachotich
priority: normal
severity: normal
status: open
title: os.makedirs with exist_ok=True raises PermissionError on Windows 7^
type: behavior
versions: Python 3.2, Python 3.3, Python 3.4, Python 3.5, Python 3.6
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue25583>
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