Mark Dickinson <[EMAIL PROTECTED]> added the comment:
This is fine. copysign isn't supposed to propagate NaNs---it's just
supposed to silently transfer the sign bit from the second argument to the
first. So I think this is correct behaviour.
Incidentally, on OS X:
>>> from math import copysign
>>> copysign(1, float('nan'))
-1.0
This is also fine, IMO. It just so happens that on OS X the 'default' NaN
has its sign bit set.
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Tracker <[EMAIL PROTECTED]>
<http://bugs.python.org/issue2900>
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