Xiang Zhang added the comment:
This is the right behaviour.
x=[1, 2, 3].append([1, 2, 3]) acts as:
x=([1, 2, 3].append([1, 2, 3])
Since append is a in-place operation it return None. Then x is None.
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nosy: +xiang.zhang
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue25363>
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