STINNER Victor added the comment: > TypeError: unorderable types: int() < NoneType()
The error message looks good to me: NoneType is the type of the None singleton: >>> type(None) <class 'NoneType'> >>> x=type(None)() >>> x is None True Do you propose to use the message "TypeError: unorderable types: int() < None"? This message looks wrong to me, None is not a type. The strange thing is the trailing parenthesis!? Why not "int < NoneType"? ---------- nosy: +haypo _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue25210> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
