Peter Eastman added the comment:
I don't believe that explanation is correct. You can just as easily get the
same problem without explicitly passing a map to exec(). For example:
def f():
script = """
print(a)
print([a for i in range(5)])
"""
a = 5
exec(script)
f()
The documentation for exec() states, "In all cases, if the optional parts are
omitted, the code is executed in the current scope." Therefore the code above
should be exactly equivalent to the following:
def f():
a = 5
print(a)
print([a for i in range(5)])
f()
But the latter works and the former doesn't. Contrary to the documentation,
the code is clearly not being executed in the same scope.
----------
resolution: not a bug ->
status: closed -> open
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue24800>
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