Alexander Belopolsky <[EMAIL PROTECTED]> added the comment: On Wed, Apr 16, 2008 at 3:40 PM, Antoine Pitrou <[EMAIL PROTECTED]> wrote: .. > Why would you want to have hash(range(a,b,c)) == hash((a,b,c)) ?
No particular reason other than that this is easy to test and gives some assurance that hash values are reasonable. > It'd be more logical to have hash(range(a,b,c)) == > hash(tuple(range(a,b,c))) ... which is not the same thing at all :) No, this is not correct because range(..) == range(..) is not the same as tuple(range(..)) == tuple(range(..)) in the proposed implementation. See Guido's example above and Benjamin's test case in the eq5 patch. __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue2603> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
