Guido van Rossum added the comment: Wait, with that f() definition I'd expect a different result from the former -- each letter as a new arg. Right? On Jan 26, 2015 8:42 AM, "Neil Girdhar" <rep...@bugs.python.org> wrote:
> > Neil Girdhar added the comment: > > >>> def f(a, *b): print(list(a), list(b)) > > ---------- > > _______________________________________ > Python tracker <rep...@bugs.python.org> > <http://bugs.python.org/issue2292> > _______________________________________ > ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue2292> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com