Tim Peters added the comment: To be clear, I agree -0.0 is "the correct" answer, and -1.0 is at best defensible via a mostly-inappropriate limit argument. But in Py3 floor division of floats returns an integer, and there is no integer -0. Nor, God willing, will there ever be ;-)
Looks to me like what (Py3's, at least) floatobject.c's floor_divmod() returns (the source of float floor division's result) when the 2nd argument is infinite is largely an accident, depending on what the platform C fmod() and floor() happen to return. So it would require special-casing an infinite denominator in that function to force any specific cross-platform result. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue22198> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
