New submission from the mulhern:
>>> def decorator(f):
... @functools.wraps(f)
... def new_func(self, junk):
... stack = inspect.stack()
... for i, frame in enumerate(stack):
... print("%s" % frame[3])
... f(self, junk)
... return new_func
...
>>> @decorator
... def junk(self, p):
... print("%s" % junk.__name__)
...
>>> junk("a", "b")
new_func
<module>
junk
>>> junk.__name__
'junk'
Note that the wrapper function itself inspects the stack, printing out the
names of methods on the stack.
Note that "junk", the name of the wrapped function does not appear on the
stack, it is only printed out by the junk method itself.
I think that the name of the function at the top of the stack should be the
name of the wrapped function, not of its wrapper. The name of the wrapper
function should not appear at all.
----------
components: Interpreter Core
messages: 220863
nosy: the.mulhern
priority: normal
severity: normal
status: open
title: stack frame contains name of wrapper method, not that of wrapped method
type: behavior
versions: Python 2.7
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue21794>
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