New submission from Jovik: This works on Linux as expected: import subprocess proc = subprocess.Popen(["./app"], stdout=subprocess.PIPE, cwd="workspace")
but on Windows I get: FileNotFoundError: [WinError 2] The system cannot find the file specified To successfully execute it on Windows I need to set shell=True first: proc = subprocess.Popen(["app.exe"], stdout=subprocess.PIPE, cwd="workspace", shell=True) which is odd since by default it should use cwd when searching for binary: "If cwd is not None, the function changes the working directory to cwd before executing the child. In particular, the function looks for executable (or for the first item in args) relative to cwd if the executable path is a relative path." from http://docs.python.org/3.3/library/subprocess.html ---------- assignee: docs@python components: Documentation messages: 213570 nosy: Jovik, docs@python priority: normal severity: normal status: open title: Different behaviour on Posix and Windows when using subprocess.Popen(..., cwd=path) type: behavior versions: Python 3.3 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue20927> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
