Alexander Belopolsky added the comment: Here is the use-case that was presented to support adding additional operations on timedelta objects:
""" I'm conducting a series of observation experiments where I measure the duration of an event. I then want to do various statistical analysis such as computing the mean, median, etc. Originally, I tried using standard functions such as lmean from the stats.py package. However, these sorts of functions divide by a float at the end, causing them to fail on timedelta objects. Thus, I have to either write my own special functions, or convert the timedelta objects to integers first (then convert them back afterwards). """ (Daniel Stutzbach, in msg26267 on issue1289118.) The proposed statistics module does not support this use case: >>> mean([timedelta(1)]) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/Users/sasha/Work/cpython-ro/Lib/statistics.py", line 387, in mean total = sum(data) File "/Users/sasha/Work/cpython-ro/Lib/statistics.py", line 223, in sum total += x TypeError: unsupported operand type(s) for +=: 'int' and 'datetime.timedelta' >>> sum([timedelta(1)], timedelta(0)) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/Users/sasha/Work/cpython-ro/Lib/statistics.py", line 210, in sum raise TypeError('sum only accepts numbers') TypeError: sum only accepts numbers ---------- nosy: +agthorr _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue18606> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com