New submission from Ram Rachum: I have a `Future` and I want to check whether it's in finished state. It seems like I don't have a method to do that, right? (I could emulate the existing methods for checking Future state, but that would mean fiddling with private variables.)
Why not just expose the Future state in a property that automatically acquires `self._condition`? (Instead of a horde of methods.) ---------- components: Library (Lib) messages: 191126 nosy: cool-RR priority: normal severity: normal status: open title: No way to check whether Future is finished? type: behavior versions: Python 3.4 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue18212> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
