Tim Peters added the comment: Nice example! Yes, the round() implementation is numerically naive, in this particular case ignoring that x+0.5 isn't necessarily representable (it multiplies the input by 10.0, adds 0.5, takes the floor, then divides by 10.0, and in this specific case adding 0.5 loses information to rounding:
>>> 5629499534213125 + 0.5 5629499534213126.0 ). __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue1694> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
