R. David Murray added the comment:

The problem with using 'nonlocal' is that it would naturally be read as 'those 
names referenced in a nonlocal statement', which I don't think is the case.  
Maybe 'non-local', to differentiate it from the keyword?

I'm attaching a patch incorporating my understanding of the suggestions made so 
far.

----------
keywords: +patch
nosy: +r.david.murray
Added file: http://bugs.python.org/file29614/locals_doc.patch

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