New submission from V.E.O:
I just learned python @ decorator, it's cool, but soon I found my modified code
coming out weird problems.
def with_wrapper(param1):
def dummy_wrapper(fn):
print param1
param1 = 'new'
fn(param1)
return dummy_wrapper
def dummy():
@with_wrapper('param1')
def implementation(param2):
print param2
dummy()
I debug it, it throws out exception at print param1
UnboundLocalError: local variable 'param1' referenced before assignment
If I remove param1 = 'new' this line, without any modify operation(link to new
object) on variables from outer scope, this routine might working.
Is it meaning I only have made one copy of outer scope variables, then make
modification?
The policy of variable scope towards decorator is different?
----------
components: Interpreter Core
messages: 169389
nosy: V.E.O
priority: normal
severity: normal
status: open
title: Python function decorator scope losing variable
type: compile error
versions: Python 2.7
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue15813>
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