Chris Jerdonek <chris.jerdo...@gmail.com> added the comment:

Thanks for the info.  A couple questions: what does "won't break" mean -- that 
it won't throw an exception of a type that it wouldn't normally throw in a 
single-threaded environment?  And does this mean that not even deque.pop() is 
atomic?

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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue15330>
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