Nikki DelRosso <nik...@gmail.com> added the comment:
I'm having the same issue as the original author of this issue was. The
workaround does not apply to the situation where the captured text is on one
side of an "or" grouping, rather than just being optional.
I'm trying to remove groups of text in parentheses that come at the end of a
string, but if the content in a pair of parentheses is a number, I want to
retain it. My regular expression looks like so:
These work:
>>> re.sub(r'(?:\((?:(\d+)|.*?)\)\s*)+$','\\1','avatar (2009)')
'avatar 2009'
>>> re.sub(r'(?:\((?:(\d+)|.*?)\)\s*)+$','\\1','avatar (2009) (special
>>> edition)')
'avatar 2009'
This doesn't:
>>> re.sub(r'(?:\((?:(\d+)|.*?)\)\s*)+$','\\1','avatar (special Traceback (most
>>> recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.6/re.py", line 151, in sub
return _compile(pattern, 0).sub(repl, string, count)
File "/usr/lib/python2.6/re.py", line 278, in filter
return sre_parse.expand_template(template, match)
File "/usr/lib/python2.6/sre_parse.py", line 793, in expand_template
raise error, "unmatched group"
sre_constants.error: unmatched groupedition)')
Is there some way I can apply this workaround to this situation?
----------
nosy: +Nikker
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue1519638>
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