New submission from Kevin Ar18:
Summary:
If you have a zip file that contains a file inside of it greater than
2GB, then the zipfile module is unable to read that file.
Steps to Reproduce:
1. Create a zip file several GB in size with a file inside of it that is
over 2GB in size.
2. Attempt to read the large file inside the zip file. Here's some
sample code:
import zipfile
import re
dataObj = zipfile.ZipFile("zip.zip","r")
for i in dataObj.namelist():
if(i[-1] == "/"):
print "dir"
else:
fileName = re.split(r".*/",i,0)[1]
fileData = dataObj.read(i)
Result:
Python returns the following error:
File "...\zipfile.py", line 491, in read bytes =
self.fp.read(zinfo.compress_size)
OverflowError: long it too large to convert to int
Expected Result:
It should copy the data into the variable fileData...
I'll try to post more info in a follow-up.
----------
components: Library (Lib)
messages: 55444
nosy: Kevin Ar18
severity: normal
status: open
title: zipfile cannot handle files larger than 2GB (inside archive)
type: compile error
versions: Python 2.6
__________________________________
Tracker <[EMAIL PROTECTED]>
<http://bugs.python.org/issue1060>
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