Jason R. Coombs <jar...@jaraco.com> added the comment:
Python 2.7 is not aware of symlinks and treats them like their targets, so it
should be able to list a symlink directory or access a file within one. For
example:
PS C:\Users\jaraco> cmd /c dir
Volume in drive C is system
Volume Serial Number is 2455-92A0
Directory of C:\Users\jaraco
11-Nov-2011 06:50 <DIR> .
11-Nov-2011 06:50 <DIR> ..
..
11-Aug-2011 10:11 <SYMLINKD> bin [Dropbox\bin\x64]
10-Aug-2011 21:00 <SYMLINKD> bin-x86 [Dropbox\bin\x86]
..
11 File(s) 6,632 bytes
27 Dir(s) 301,972,422,656 bytes free
PS C:\Users\jaraco> python
Python 2.7.2 (default, Jun 12 2011, 14:24:46) [MSC v.1500 64 bit (AMD64)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.listdir('bin')
['curl.exe', 'devcon.exe', 'HotSwap!.EXE', 'Notepad2.exe', 'utorrent.exe',
'vncviewer.exe']
>>> with open('bin/curl.exe', 'rb') as f:
... f.read()[:10]
...
'MZ\x90\x00\x03\x00\x00\x00\x04\x00'
>>> ^Z
Because Python 2.7 is feature-frozen, symlink support will not be available in
Python before 3.2.
If you are experiencing errors, please reopen this ticket and describe what you
are doing, what you expect, and what you get instead.
----------
resolution: -> wont fix
status: open -> closed
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue13412>
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