Ezio Melotti <ezio.melo...@gmail.com> added the comment: I don't see where is the bug. If you do >>> lists = [[]] * 3 >>> lists [[], [], []]
you are creating a list that contains 3 references to the same list, as you can see here: >>> lists[0] is lists[1] is lists[2] True >>> [id(l) for l in lists] [33714832, 33714832, 33714832] so if you append an element to either of the inner list, it will show up 3 times, because the 3 lists are really the same object: >>> lists[0].append(3) >>> lists [[3], [3], [3]] However, if you do >>> lists[0] = 1 >>> lists [1, [3], [3]] you are replacing the first element of 'lists' with the int 1. This doesn't mutate the inner list, and therefore the second and third elements are not affected. See also http://python.net/crew/mwh/hacks/objectthink.html ---------- nosy: +ezio.melotti resolution: -> invalid stage: -> committed/rejected status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue12951> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
