Miguel de Val Borro <miguel.de...@gmail.com> added the comment: Thanks, I need the fractional day added to the ordinal day of the month. Using the timedelta division it would be:
>>> from __future__ import division >>> dt = datetime.datetime(2008, 5, 8, 13, 35, 41, 567777) >>> dt.day + (dt-datetime.datetime(dt.year, dt.month, >>> dt.day))/datetime.timedelta(1) 8.566453330752315 Then it simply becomes a one line function so I'm closing this ticket. ---------- status: pending -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue12772> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
