Ezio Melotti <ezio.melo...@gmail.com> added the comment: Using the func%(args) syntax is not possible because fab = foo%(1,2) is equivalent to fab = foo.__mod__((1,2))
It might actually be possible to overload the % operator to make something that looks like your proposed syntax (without changing the actual Python syntax), but it still look hackish to me. (We are also moving away from the % overload used by strings for the formatting in favor of the .format() method.) ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue12548> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
