zy <cdq...@gmail.com> added the comment:
> So the correct result for b'\xff\n'.decode('gb2312', 'replace') is u'?\n'?
I think it should be so. This behavior does not leave out possible information,
has no side-effect on later decodings, and should the '\n' indeed be
redundant, an output of u'?\n' would unlikely cause confusions.
Though, I have no knowledge on this subject code-wise. If a change of the
behavior will have an impact on performance, maybe the change should not come
in.
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue12016>
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