Can you file a bug report for this? I'm guessing that the trace code
has some bad interaction with LOAD_LOCALS, such that a free variable
passed through the class gets treated as local instead. I can
reproduce this problem in Python 2.4, so it's a long-standing bug.
Also, as a matter of terminology, there is no currying going on. It's
just a problem with closures.
Jeremy
On 10/1/06, Scott Marks <[EMAIL PROTECTED]> wrote:
> The code below exhibits different behavior depending on whether it invokes
> sys.settrace ('-t' option) or not. This means that (in a more complicated
> case) debugging the code (which uses sys.settrace) makes it fail. Any
> ideas?
>
> """ Demonstrace that tracing messes up curried class definitions """
>
> # Some simple command line parsing: -t or --trace means trace, nothing
> means don't trace
> import sys
>
> def usage( ):
> print 'Usage:', sys.argv[ 0 ], '[-t | --trace]'
> sys.exit( 1 )
>
> if 1 == len( sys.argv ):
> pass
> elif 2 == len( sys.argv ):
> if sys.argv[ 1 ]=='-t' or sys.argv[ 1 ]=='--trace':
> def trace ( frame, event, arg ):
> # print frame, event, arg
> return trace
> sys.settrace( trace )
> else:
> usage( )
> else:
> usage( )
>
>
>
> # The test: define a class factory with a curried member function
>
> def the_factory( parm1 ):
> class the_class( object ):
> def curried( self ): return parm1
> return the_class
>
> x = the_factory( 42 )
>
> y = x( )
>
> try:
> x.parm1
> print "Failure: x (the manufactured class) has attribute parm1?!"
> except AttributeError:
> print "Success with the manufactured class!"
>
> try:
> y.parm1
> print "Failure: y (the instance) has attribute parm1?!"
> except AttributeError:
> print "Success with the instance!"
>
> assert y.curried( ) == 42, "Currying didn't work?!"
>
>
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>
>
>
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