Bugs item #1531963, was opened at 2006-07-31 15:58
Message generated for change (Comment added) made by collinwinter
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Category: Python Library
>Group: Python 2.5
>Status: Closed
Resolution: Fixed
Priority: 5
Private: No
Submitted By: hakker.de (hakker_de)
Assigned to: Nobody/Anonymous (nobody)
Summary: SocketServer.TCPServer returns different ports
Initial Comment:
Providing 0 as a port in __init__ of
SocketServer.TCPServer leads to different values for
port in server_address and socket.getsockname().
Example:
import SocketServer
s = SocketServer.TCPServer(("0.0.0.0", 0), Handler)
s.server_address
-> ('0.0.0.0', 0)
s.socket.getsockname()
-> ('0.0.0.0', 39129)
s.server_address should also contain 39129 as the
port number for the free port found.
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>Comment By: Collin Winter (collinwinter)
Date: 2007-03-09 22:33
Message:
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Originator: NO
Fixed in r54253 (for 2.6), r54255 (for 2.5.1). Thanks for the bug report!
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Comment By: Collin Winter (collinwinter)
Date: 2007-03-09 19:32
Message:
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hakker, you marked this as "fixed"; was that intentional?
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Comment By: Damon Kohler (damonkohler)
Date: 2006-08-22 21:36
Message:
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user_id=705317
Patch 1545011 is a proposed fix.
----------------------------------------------------------------------
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