Terry J. Reedy <tjre...@udel.edu> added the comment: I think Nick's point, and one I agree with, is (or amounts to): 'somelist += ob' == 'somelist.__iadd__(ob)' == 'somelist.extend(ob)' == 'somelist[len(somelist):len(somelist)]=ob' is defined and should be implemented for all somelist,ob pairs. If ob is an iterable, add the items at the end; if not, raise TypeError.
CPython currently has a bug that breaks the middle equality in a peculiar case. We recognize that and hope to fix it. The proper, future-proof fix for Greg Price & Co. is for them to 1. use somelist.append(ob) to append a single object, iterable or not, to somelist. If they insist on (mis)using += for appending, 2. add the trivial __iter__ yielding just the instance to all classes whose instances are ever a target of 'somelist += instance'. Or 3. wrap each non-iterable instance in an iterable, such as a tuple: "somelist += (non-iterable,). Any of these (1. actually) should have been done in the first place, as has always been documented. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue11477> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
