New submission from Daniel Urban <urban.dani...@gmail.com>:
inspect.getcallargs raises TypeError if given a function with only **kwargs,
and some keyword arguments:
Python 3.3a0 (py3k:88451, Feb 20 2011, 12:37:22)
[GCC 4.4.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>>
>>> from inspect import getcallargs
>>>
>>> def f(**kwargs): pass
...
>>> f(a=1, b=2)
>>>
>>> getcallargs(f, a=1, b=2)
Traceback (most recent call last):
...
TypeError: f() takes no arguments (2 given)
In line 946 of inspect.py the "num_args == 0 and num_total" condition is true:
the function expects 0 positional arguments and got more than zero arguments,
but in this case these are keyword arguments, so it shouldn't raise TypeError.
----------
components: Library (Lib)
messages: 128902
nosy: benjamin.peterson, durban, gsakkis
priority: normal
severity: normal
status: open
title: inspect.getcallargs raises TypeError on valid arguments
type: behavior
versions: Python 2.7, Python 3.2, Python 3.3
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue11256>
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