Bugs item #1621367, was opened at 2006-12-23 11:04
Message generated for change (Comment added) made by mark-roberts
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Category: Extension Modules
Group: Python 2.5
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Msword (msword)
Assigned to: Nobody/Anonymous (nobody)
Summary: random import works?
Initial Comment:
I'm just starting working with python, and it seems that random.choice() isn't
all that random. After running the program(attached) a few times, each and
every time it selects 1 < 2 < 3 < 4 < 5 and I can expect this to happen,
meaning it isn't all that random.
Email: [EMAIL PROTECTED]
Thanks
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Comment By: Mark Roberts (mark-roberts)
Date: 2006-12-26 02:51
Message:
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This is an issue with the way you have written your initial application.
See the attachment that I've supplied to explain what is going wrong in
your program. It really boils down to you adding X to each value, while X
is steadily increasing in value (1, 2, 3, 4, 5). At one point, you
actually add 1 to one value, and add 5 to another (for the same random
choice).
- Mark
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Comment By: Dennis Allison (dallison)
Date: 2006-12-23 12:32
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I believe the problem is with your test framework and not with
random.choice(). The library function random.choice( seq ) selects, using a
uniform distribution, one item from the sequence at each call. By the law
of large numbers, if you have K items in the sequence, each should be
returned K/N times, on average, after N calls. You should expect
deviations even for fairly large N. If you want to test the randomess, use
a chi-square test to test against the hypothes of uniform random selection
with replacement. Of course there are many other statistical properties
which ought to be checked, for example, the distribution of runs.
Consider the program:
import random
dist = [0,0,0,0,0]
for i in range(100000):
j = random.choice([0,1,2,3,4])
dist[j] += 1
print dist
which prints the distribution observed for each choice. With
100000 tries you'd expect each one to appear (on average) 20000
time. Running it on my a three times gives:
[19839, 19871, 19996, 20035, 20259]
[20043, 19870, 20025, 20109, 19953]
[19947, 20033, 19970, 20111, 19939]
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