Bugs item #1396543, was opened at 2006-01-04 04:57
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Category: Python Library
Group: Python 2.4
Status: Open
Resolution: None
Priority: 5
Submitted By: John Hansen (johnhansen)
Assigned to: Nobody/Anonymous (nobody)
Summary: urlparse is confused by /
Initial Comment:
If the parameter field of a URL contains a '/', urlparse does not enter date
in the parameter field, but leaves it attached to the path.
The simplified example is:
>>> urlparse.urlparse("http://f/adi;s=a;c=b/";)
('http', 'f', '/adi;s=a;c=b/', '', '', '')
>>> urlparse.urlparse("http://f/adi;s=a;c=b";)
('http', 'f', '/adi', 's=a;c=b', '', '')
The realworld case was:
>>> urlparse.urlparse("http://ad.doubleclick.net/adi/
N3691.VibrantMedia/B1733031.2;sz=160x600;click=http%3A/
adforce.adtech.de/adlink%7C82%7C59111%7C1%7C168%7CAdId%
3D1023327%3BBnId%3D4%3Bitime%3D335264036%3Bku%3D12900%
3Bkey%3Dcomputing%2Bbetanews%5Fgeneral%3Blink%3D")
(''http'', 'ad.doubleclick.net/adi/N3691.VibrantMedia/
B1733031.2;sz=160x600;click=http%3A/adforce.adtech.de/adlink%
7C82%7C59111%7C1%7C168%7CAdId%3D1023327%3BBnId%3D4%3Bitime
%3D335264036%3Bku%3D12900%3Bkey%3Dcomputing%2Bbetanews%
5Fgeneral%3Blink%3D', '', '', '')
What's odd is that the code specifically says to do this:
def _splitparams(url):
if '/' in url:
i = url.find(';', url.rfind('/'))
if i < 0:
return url, ''
Is there a reason for the rfind?
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