Bugs item #1106572, was opened at 2005-01-21 10:42
Message generated for change (Comment added) made by birkenfeld
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Category: Python Library
Group: None
>Status: Closed
>Resolution: Fixed
Priority: 5
Submitted By: Andreas Jung (ajung)
Assigned to: Nobody/Anonymous (nobody)
Summary: os.makedirs() ignores mode parameter
Initial Comment:
os.makedirs('foo/x', 0777) does not create the directories
with permissions g+rwx,u+rwx,o+rwx but instead:
>>> import os
>>> os.makedirs('foo/xx', 0777)
>>>
[2]+ Stopped python2.3
[EMAIL PROTECTED]:~/sandboxes/haufecms/instance/Products/HaufeCMS:
ls -la foo
insgesamt 12
drwxr-xr-x 3 ajung ajung 4096 2005-01-21 10:39 .
drwxr-xr-x 19 ajung ajung 4096 2005-01-21 10:39 ..
drwxr-xr-x 2 ajung ajung 4096 2005-01-21 10:39 xx
This happens with Python 2.3.4 on Linux
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>Comment By: Reinhold Birkenfeld (birkenfeld)
Date: 2005-12-17 18:15
Message:
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Clarified the docs in rev. 41732/41733.
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Comment By: Andreas Jung (ajung)
Date: 2005-01-26 14:22
Message:
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umask(0) does the job. In this case the documentation is
completely misleading. The API reads as the 'mode' parameter
is *the* umask.
----------------------------------------------------------------------
Comment By: Wummel (calvin)
Date: 2005-01-24 13:48
Message:
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What is the current process umask? The resulting directory
mode will always be (mode & ~umask & 0777).
To be sure that os.makedirs() will use the given mode
without modification, you have to execute os.umask(0)
beforehand.
So this bug is probably invalid if you forgot to set your
umask accordingly.
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