Bugs item #1119282, was opened at 2005-02-09 08:27 Message generated for change (Settings changed) made by rhettinger You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1119282&group_id=5470
Category: Documentation Group: Python 2.4 >Status: Closed >Resolution: Invalid Priority: 5 Submitted By: Kent Johnson (kjohnson) Assigned to: Nobody/Anonymous (nobody) Summary: Docs for set() omit constructor Initial Comment: The documentation for set() and frozenset() in the library reference section 2.3.7 has no explicit description of how to create a set or frozenset. IOW, nowhere does it say what the argument(s) to set() and frozenset() are. The text from section 5.15 (the sets module) should be usable here. ---------------------------------------------------------------------- Comment By: Raymond Hettinger (rhettinger) Date: 2005-02-09 13:51 Message: Logged In: YES user_id=80475 Following the style for list(), dict(), and tuple(), the constructor for set() and frozenset() is documented in section 2.1 (builtin functions). ---------------------------------------------------------------------- Comment By: Kent Johnson (kjohnson) Date: 2005-02-09 08:37 Message: Logged In: YES user_id=49695 Ah, it's documented in section 2.1, Built-in Functions. A cross-reference from section 2.3.7 might be helpful...e.g. "Instances of set and frozenset may be created by calling the set() and frozenset() built-in functions; see Section 2.1, Built-in Functions, for details." BTW the same suggestion applies for dict(), list() and tuple() - some mention of them in sections 2.3.6 and 2.3.8 seems appropriate. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1119282&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
