If you run the following code with Python 3, you will not recieve a
exception; dispite it being blatently wrong.
import sys
from PyQt4 import QtGui, QtCore
class FooThread(QtCore.QThread):
def run(self):
beeswax
return
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
ft = FooThread()
ft.start()
sys.exit(app.exec_())
Avaris on #pyqt @ freenode managed to come up with this workaround:
import sys
import time
import traceback
from PyQt4 import QtGui, QtCore
def excepthook(exc_type, exc_val, tracebackobj):
message = ''.join(traceback.format_exception(exc_type, exc_val,
tracebackobj))
print('EXCEPTHOOK')
print(message)
print('*'*30)
sys.excepthook = excepthook
class FooThread(QtCore.QThread):
def run(self):
time.sleep(1)
beeswaxThread
class FooObject(QtCore.QObject):
finished = QtCore.pyqtSignal()
def run(self):
time.sleep(2)
beeswaxObject
self.finished.emit()
if __name__ == "__main__":
app = QtCore.QCoreApplication(sys.argv)
thread = QtCore.QThread()
fooObject = FooObject()
fooObject.moveToThread(thread)
thread.started.connect(fooObject.run)
fooObject.finished.connect(thread.quit)
fooThread = FooThread()
thread.start()
fooThread.start()
QtCore.QTimer.singleShot(3000, app.quit)
sys.exit(app.exec_())
My test system that I use to reproduce this is:
PyQt 4.9.6 - Built from source.
Ubuntu 12.10
Pythion 3.2
The guys on IRC confirmed this was a bug for me too.
--
Thanks, Richie Ward
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