if you need to return 2 dicts :
*@view_config(route_name="special_view', renderer='json')*
*def special_view(request)*
* return {'viewA': **ViewOne(request).view_a()['viewA']**, 'viewB': *
*ViewTwo(request).**view_b()**['viewA']**}*
This will throw KeyError exception if returned dicts don't contain key
'viewA'.
if you need to overwrite dict from ViewOne() with dict from ViewTwo():
ret_dict = *ViewOne(request).view_a()['viewA']*
ret_dict.update(*ViewTwo(request).**view_b()**['viewA']*)
return {'viewA' : ret-dict}
On Friday, February 28, 2014 11:15:57 AM UTC+1, Chung WONG wrote:
>
> Hi all,
>
> Say If there are two views as below:
>
> *class ViewOne(object):*
> * def __init__(self, request):*
> * self.request=request*
>
> * @view_config(route_name='a', renderer='json')*
> * def view_a(self):*
> * return {'viewA: some_dict}*
>
> *class ViewTwo(object):*
> * def __init__(self, request):*
> * self.request=request*
>
> * @view_config(route_name='b', renderer='json')*
> * def view_b(self):*
> * return {'viewA: some_dict_too}*
>
>
> both of them return response as json. What is the best way to combine both
> responses as a single response in another views?
> For example:
>
>
> *@view_config(route_name="special_view', renderer='json')*
> *def special_view(request)*
> * return {'viewA: some_dict, 'viewB': some_dict_too}*
>
>
> I tried using subrequest, however, I couldn't find a way to merge the two
> responses returned by the two views.
>
> Thanks in advance.
>
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