On Monday, 5 March 2012 at 11:37, flex wrote: > hi, all: > > i want to require my own ruby class in a custom function, now i put the ruby > file in the same directory with custom function, and require it in the > function file like this: > > require File.join([File.expand_path(File.dirname(__FILE__)), 'test.rb']) > > but i think this is too ugly, is there any other way? > > -- > System Administrator, Focus on System Management and Basic Development > -- > You received this message because you are subscribed to the Google Groups > "Puppet Users" group. > To post to this group, send email to puppet-users@googlegroups.com > (mailto:puppet-users@googlegroups.com). > To unsubscribe from this group, send email to > puppet-users+unsubscr...@googlegroups.com > (mailto:puppet-users+unsubscr...@googlegroups.com). > For more options, visit this group at > http://groups.google.com/group/puppet-users?hl=en.
Hi, I'm doing something like this in my scripts (not exactly puppet custom modules/facts but it will do the trick): $LOAD_PATH << File.expand_path(File.dirname(__FILE__) + '/../lib') then you can use `require test' construction. Best, -- Dominik Zyla -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To post to this group, send email to puppet-users@googlegroups.com. To unsubscribe from this group, send email to puppet-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/puppet-users?hl=en.
