"Marcus, Allan B" <al...@lanl.gov> writes:
> How does puppet determine the macaccess fact? For example, my MacPro has two
> enternet ports.
>
> macaddress => 00:25:00:ef:fb:ce
> macaddress_en0 => 00:25:00:ef:cf:a1
> macaddress_en1 => 00:25:00:ef:fb:ce
>
> if I change the wire to the other port (and set the IP address appropriately
> in network), I get the same factor results. It seems factor always report
> en1 as the "macaddress". Is "macaddress" supposed to be the active mac
> address? I suppose it would be difficult to determine 'active' if the
> computer was plugged into two networks at the same time, but that is rarely
> the case in my environment.
>
> Any ideas on how to get the 'active' mac address?
Er, you noted that you "fixed" this elsewhere, but...
The 'macaddress' "fact" is a load of random garbage with no meaningful
connection to reality: it picks a random address from the output of ifconfig,
rather than anything useful.
The idea of an "active" MAC is meaningless: my laptop currently has two
"active" MAC addresses:
192.168.1.0/24 dev eth0 proto kernel scope link src 192.168.1.45 metric 1
192.168.201.0/24 dev wlan0 proto kernel scope link src 192.168.201.109
metric 2
169.254.0.0/16 dev eth0 scope link metric 1000
default via 192.168.1.1 dev eth0 proto static
macaddress_eth0 => 00:1c:25:1e:26:6f
macaddress_wlan0 => 00:1d:e0:55:48:45
There is no meaningful way to talk about one of those being "active" to the
exclusion of the other: both are active, have real routes, and are interacting
with external devices. You can even fail-over traffic between the two.
The right fix would be to put that poor, meaningless fact to sleep before
someone mistakes it for something actually *significant*.
Daniel
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✣ Daniel Pittman ✉ dan...@rimspace.net ☎ +61 401 155 707
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