foo.bar1 = 1 foo.bar2 = 2 foo.bar3 = 3 foo["bar1"] = 1 foo["bar2"] = 2 foo["bar3"] = 3
Doing this 20 times is kinda clumsy. And __dict__ doesnt work. -- You received this message because you are subscribed to the Google Groups "Protocol Buffers" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/protobuf. For more options, visit https://groups.google.com/d/optout.
