Aha, I just discovered you can do: count without (instance, job) (agent_build_info) group without (instance, job) (agent_build_info)
That should be what you want :-) On Thursday, 24 August 2023 at 18:59:24 UTC+1 Brian Candler wrote: > If you are happy to list all the labels of interest (i.e. everything apart > from the 'job' and 'instance' labels and any other labels you've added > yourself): > > count by (goversion,version,branch,revision) (agent_build_info) > > Or you can use "group by" instead of "count by" to get a value of 1 for > everything (although personally I think the counts are useful!) > > On Thursday, 24 August 2023 at 16:05:17 UTC+1 Richie wrote: > >> or i suppose i could process the results as they come from the api via >> python >> >> On Thursday, August 24, 2023 at 10:59:18 AM UTC-4 Richie wrote: >> >>> I would like to pull a line by line list of unique instances from >>> agent_build_info and save it to a file for the purpose of cross checking >>> via script against a list of known instances that should be monitored >>> (reporting purposes). >>> >>> so in short is it possible to create a query that equivalent of *select >>> distinct instance from agent_build_info --(were it a traditional table) * >>> ? >>> >>> -Richie >>> >>> -- You received this message because you are subscribed to the Google Groups "Prometheus Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/prometheus-users/7504e587-daa2-4980-b27e-45c6fff9682an%40googlegroups.com.
