Not in the presence of counter resets, no. > My full question, reason for the question, and experiment is here: https://github.com/dsabsay/prom_rates_and_counters/blob/main/README.md
"In other words, can one get the equivalent of increase(some_metric[1d]) by using the output of a recording rule like rate(some_metric[5m])? I think that increase(...) doesn't work in the way you think it does. increase(...) and rate(...) are the same thing, only differing by a factor of the time window. That is: increase(some_metric[1d]) is *exactly* the same as rate(some_metric[1d])*86400. To find the exact difference between a metric now and 1d ago, you can use some_metric - some_metric offset 1d However that does not work across counter resets, for obvious reasons. The underlying requirement you have is, I think, given a collection of recorded rate[5m] values, can you turn this into a rate[1d] ? I think the avg_over_time() of those rates is the best you can do. If these are 5m rates, then you'd want 5 minute steps: avg_over_time( [ xx : 5m] ) But you are testing this over very short time periods (10m) and therefore it's not going to be exact. In particular, rate([5m]) takes the rate between the first and last data points in a 5 minute window. This means that if you are scraping at 1 minute intervals, you're actually calculating a rate over a 4 minute period. On Thursday, 29 June 2023 at 07:22:43 UTC+1 Daniel Sabsay wrote: > Is it possible to accurately calculate original counts from pre-recorded > rates? > My experiments suggest the answer is no. But I’m curious to get other > perspectives to see if I’ve overlooked something or if there is a more > effective way to approach this. > > My full question, reason for the question, and experiment is here: > https://github.com/dsabsay/prom_rates_and_counters/blob/main/README.md > > Thanks! > -- You received this message because you are subscribed to the Google Groups "Prometheus Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/prometheus-users/19209590-7c4f-452e-ab0c-be3f0e52cad7n%40googlegroups.com.
