Whil Hentzen wrote:
> Actually, yes. :)
>
> Suppose the stock market is dropping 10 points a day for a month. Then
> on day 32 it drops 11 points, then on day 33 it drops 12 points, on day
> 34 it drops 13 points. It's dropping (decreasing) at an increasing rate.
>
> When something increases at the same rate, velocity is constant,
> acceleration is 0. When velocity increases, acceleration is > 0. When
> velocity decreases, acceleration is < 0.
>
> And when acceleration increases.... well, that may be more than we all
> want to discuss right now. :)
>
> Whil


Duh...of course!  Consider me edu-ma-cated by them thar skollers on that
Foxpro thingee website.





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