[PHP-WIN] Re: Jaw Breaker - What's the ansewer?

[M. Sokolewicz]

JC Botha wrote:
The following is a section of PHP code (see Apache.org and PHP.net).
  function f($c) {
    $c++;
    if ($c % 2) { return f($c); }
    return $c++;
  }
  
  function g($n) {  
    for ($i=1;$i<10;$i++) {
      $n = f($n*$i);
    }
    return ($n);
  }
    
  print(g($x));

What is the smallest value that $x can have if 4277108 is outputted to
the screen after running this code?
$x is a number between 1 and 10 and has 2 decimal places.
it's not a jawbreaker, it's impossible IMO.
f() always returns the number if it's uneven, or if it's even, it 
returns (n+1). So, it always returns uneven. which means the result of 
g() can *never* be even.

[[side note:
unless "return $c++;" does first add 1 to it before returning, but I 
think it doesn't, since it's a postincrement operator.
]]

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