Thanks...that did the trick very nicely!
i appreciate the help.
Ron
>From: Jeremy Schreckhise
>To: php-windows@lists.php.net
>Sent: 01/31/2005 12:56 PM
>You could also do:
> $daystosubtract = 3;
> $mydate =
>(date("m/d/y",mktime(0,0,0,date("m"),date("d")-$daystosubtract,date("Y"))
));
>
>Jeremy Schreckhise
>
>"Jason Barnett" <[EMAIL PROTECTED]> wrote in message
>news:[EMAIL PROTECTED]
>> Ron Herhuth wrote:
>> > I am trying to construct a function where I feed it a number such as
"x"
>> > it returns the date "x" days ago.
>>
>> <?php
>>
>> $format = 'l dS of F Y h:i:s A';
>>
>> /** Check that "now" relative time is ok, instead of midnight */
>> echo date($format, strtotime("now")) . "\n";
>>
>> /** If now resolves correctly, then this should work */
>> $x = strtotime("-1 days");
>> echo date($format, $x);
>>
>> ?>
>>
>> >
>> > I tried checking out several resources that give you the difference
>> > between two dates, but not exactly what I was looking for. I was
just
>> > hoping someone had a little algorithm in their bag of tricks.
>> >
>> > Thanks,
>> > Ron
>> >
>>
>>
>> --
>> Teach a man to fish...
>>
>> NEW? | http://www.catb.org/~esr/faqs/smart-questions.html
>> STFA | http://marc.theaimsgroup.com/?l=php-general&w=2
>> STFM | http://www.php.net/manual/en/index.php
>> STFW | http://www.google.com/search?q=php
>> LAZY |
>>
>http://mycroft.mozdev.org/download.html?name=PHP&submitform=Find+search+p
lugins
>
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