Justin
I copied your php string with the ; at the end and as before nothing :( When looking at the HTML source after the page has been parsed the following is there:
<a href="javascript:openWindow();"></a> so the <img> tag is completely skipped.
Justin Patrin wrote:
On Sat, 31 Jul 2004 17:33:50 +0200, Schalk Neethling
<[EMAIL PROTECTED]> wrote:
Hi there
I have a line of PHP code that behaves very strangely, I was hoping someone can shed some light on this.
When the line reads as follows: <?php echo '<a href="javascript:openWindow();">'.$row_ads['full_img'].'</a>' ?> it works find and the output is displayed. Now, when I change the line as follows no output is produced.
<?php echo '<a href="javascript:openWindow();"><img src="'.$row_ads['full_img'].'" width="87" height="120" /></a>' ?>
1) Put a semi-colon at the end of the line. 2) I would suggest not using the PHP tags inline as it makes the code hard to read 3) Have you looked at the source HTML for the page to see if anything gets output?
<?php echo '<a href="javascript:openWindow();"><img src="'.$row_ads['full_img'].'" width="87" height="120" /></a>'; ?>
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-- Kind Regards Schalk Neethling Web Developer.Designer.Programmer.President Volume4.Development.Multimedia.Branding emotionalize.conceptualize.visualize.realize Tel: +27125468436 Fax: +27125468436 email:[EMAIL PROTECTED] web: www.volume4.co.za
This message contains information that is considered to be sensitive or confidential and may not be forwarded or disclosed to any other party without the permission of the sender. If you received this message in error, please notify me immediately so that I can correct and delete the original email. Thank you.
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