----- Original Message ----- 
From: malte 
To: [EMAIL PROTECTED] 
Sent: Monday, September 22, 2003 10:43 PM
Subject: Re: [PHP-WIN] Problem with 2 buttons


what do you need this for? -><input type="hidden" name="CHANGE">
it does nothing

give your image inputs hard-coded values, like  
<input type="image" name="cancel" src="bla.gif" value="true">
<input type="image" name="cancel" src="bla.gif" value="false">

and don't use isset try:

 if($cancel=='true') do_some_stuff();
  ----- Original Message ----- 
  From: William Cheung 
  To: [EMAIL PROTECTED] 
  Sent: Monday, September 22, 2003 7:43 PM
  Subject: [PHP-WIN] Problem with 2 buttons


  I have 2 buttons sitting next to each other. One to update; the other to cancel. 
However, no matter which button I click, the isset($_POST["CHANGE"]) always returns 
true. My template code is list below. Could someone tell me what's wrong with my code?



  <tr height=60>

         <td width="5%">&nbsp;</td>

         <td valign=bottom>

                     <input type="hidden" name="CHANGE">

                     <input type=image name=CHANGE 
src={#img_dir#}{#template#}page6grid_g3.gif 
onmouseover="this.src='{#img_dir#}{#template#}page6grid_g4.gif'" 
onmouseout="this.src='{#img_dir#}{#template#}page6grid_g3.gif'">

                     <font class=mpanel_mid_data style="font-weight: lighter;">Update 
order</font>

         </td>

         <td valign=bottom>

                     <input type="hidden" name="CANCEL">

                     <input type=image name="CANCEL" 
src={#img_dir#}{#template#}page6grid_g11.gif 
onmouseover="this.src='{#img_dir#}{#template#}page6grid_g12.gif'" 
onmouseout="this.src='{#img_dir#}{#template#}page6grid_g11.gif'">

                     <font class=mpanel_mid_data style="font-weight: lighter; 
text-indent: 0px;">Cancel order</font>

         </td>

  </tr>



  William Cheung B.Sc, MCSE, MCDBA

  Databyte Corp. 


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