Depends if you want records with the same YYYY-MM-DD (my example) or YYYY (your example).
After re-reading the original post it appears he only wants results as per your query, oops :) Cheers Mike > -----Original Message----- > From: Uttam [mailto:[EMAIL PROTECTED] > > isn't it better to just: > > SELECT DISTINCT YEAR(<date>) FROM <table>; > > > > regds, > > -----Original Message----- > From: Michael Power [mailto:[EMAIL PROTECTED] > > Better yet define the required dataset with SQL to speed the > whole process > up: > > "SELECT YEAR(your_date) FROM table_name GROUP BY your_date"; > > Cheers > Mike > > > "Matt Hillebrand" > > array_unique() > > > > |-----Original Message----- > > |From: Per Christian [mailto:[EMAIL PROTECTED] > > | > > |Hi > > | > > |I'm building a PHP project for fun, and are going to get > some dates > > |from my database (mysql). The problem is that I only want > the year, > > |but the date is in the format YYYY-MM-DD so I get the whole column > > |and remove the -MM-DD part, but now I have a lot of the > same year Is > > |there a function or some code that removes duplicate > entries from a > > |array? > > | > > |Best Regards, > > |Per Christian > > > > -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
