I'm not sure what you are talking about here so I will have to guess...

If by JAVA you mean javascript, well that operates client side and it cannot
directly interact with a server side PHP script which has finished execution
by the time the page is displayed.

If you are trying to display data when the user clicks on a form object then
I would look into using DHTML or CSS to unhide a previously populated but
hidden div/layer. Alternatively javascript can open another window, or have
the form re-submit with different parameters - naturally the latter 2 will
involve another round trip to the server....

HTH
Rich

-----Original Message-----
From: A. Mikkelsen [mailto:a__mikkelsen@;hotmail.com]
Sent: 12 November 2002 12:41
To: [EMAIL PROTECTED]
Subject: [PHP-WIN] HELP - problems with mysql and select .


Hey.

I'm trying to make a page with a dropdown (data from MYSQL) where I with a
click on the choosen line get the information an the user in a table beneth.

The dropdown box works, but the click part and the java part  doesn't...

Can anyone help ????

JAVA Function :

function show()
  {
   show_list = 1;
  }


CODE :

 <TR>
  <TD COLSPAN="2">
   <FORM METHOD = "post" NAME="update_user" ACTION = "<? echo $PHP_SELF ?>">
  <INPUT TYPE="Hidden" NAME="action" VALUE="show_users">
   <SELECT NAME="wm_id" SIZE="6" STYLE="width=205px">
  <?php
   $show_list = 0;
   $user_list = generate_user_id_list();
   For ($i=0; $i < sizeof($user_list); $i++)
    {
    echo "<OPTION VALUE=".$user_list[$i]['wm_id']."
onClick=show()>".$user_list[$i]['wm_id']." - ".$user_list[$i]['f_name']."
".$user_list[$i]['l_name']."</OPTION>";
   }
   ?>
  </TD>
 </TR>
 <TR>
  <TD>
  <br>
  <br>
  <br>
  <INPUT TYPE="Submit" VALUE="View user" SIZE="10" onClick="show()">
  </TD>
  </TR>
  <TR>
   <TD>
    <?php
     IF (!$show_list == 0)
   {
    echo "<br><br><br><br>TEST";
   }
    ?>
   </TD>
  </TR>




//A. Mikkelsen



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